938. Range Sum of BST - LeetCode Solution


Tree Binary Tree DFS BFS

Python Code:

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def rangeSumBST(self, root: Optional[TreeNode], L: int, R: int) -> int:
        if not root:
            return 0
        elif root.val < L:
            return self.rangeSumBST(root.right, L, R)
        elif root.val > R:
            return self.rangeSumBST(root.left, L, R)
        
        return root.val + self.rangeSumBST(root.left, L, R) + self.rangeSumBST(root.right, L, R)


Comments

Submit
0 Comments
More Questions

1666F - Fancy Stack
1354A - Alarm Clock
1543B - Customising the Track
1337A - Ichihime and Triangle
1366A - Shovels and Swords
919A - Supermarket
630C - Lucky Numbers
1208B - Uniqueness
1384A - Common Prefixes
371A - K-Periodic Array
1542A - Odd Set
1567B - MEXor Mixup
669A - Little Artem and Presents
691B - s-palindrome
851A - Arpa and a research in Mexican wave
811A - Vladik and Courtesy
1006B - Polycarp's Practice
1422A - Fence
21D - Traveling Graph
1559B - Mocha and Red and Blue
1579C - Ticks
268B - Buttons
898A - Rounding
1372B - Omkar and Last Class of Math
1025D - Recovering BST
439A - Devu the Singer and Churu the Joker
1323A - Even Subset Sum Problem
1095A - Repeating Cipher
630F - Selection of Personnel
630K - Indivisibility